(20p^(2))/(48-10p^(2))=1

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Solution for (20p^(2))/(48-10p^(2))=1 equation:


D( p )

48-(10*p^2) = 0

48-(10*p^2) = 0

48-(10*p^2) = 0

48-10*p^2 = 0

-10*p^2 = -48 // : -10

p^2 = 24/5

p^2 = 24/5 // ^ 1/2

abs(p) = (24/5)^(1/2)

p = (24/5)^(1/2) or p = -(24/5)^(1/2)

p in (-oo:-(24/5)^(1/2)) U (-(24/5)^(1/2):(24/5)^(1/2)) U ((24/5)^(1/2):+oo)

(20*p^2)/(48-(10*p^2)) = 1 // - 1

(20*p^2)/(48-(10*p^2))-1 = 0

(20*p^2)/(48-10*p^2)-1 = 0

(20*p^2)/(48-10*p^2)+(-1*(48-10*p^2))/(48-10*p^2) = 0

20*p^2-1*(48-10*p^2) = 0

30*p^2-48 = 0

(30*p^2-48)/(48-10*p^2) = 0

(30*p^2-48)/(48-10*p^2) = 0 // * 48-10*p^2

30*p^2-48 = 0

30*p^2 = 48 // : 30

p^2 = 8/5

p^2 = 8/5 // ^ 1/2

abs(p) = (8/5)^(1/2)

p = (8/5)^(1/2) or p = -(8/5)^(1/2)

p in { (8/5)^(1/2), -(8/5)^(1/2) }

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